Module 2: Equilibrium
Equilibrant: The force which is equal in magnitude, opposite in direction and collinear to the resultant force is called as equilibrant. This equilibrant cancel the effect of resultant force (or the force system) acting on the body. Question: Find support reactions. Portion CD is an extended part of the beam AB. Solution: Applying the conditions of equilibrium to beam AB, Σ M A = 0 (H A x 0) + (V A x 0) + 40 – (100sin30 0 x 3) – (100cos30 0 x 0.5) – (25 x 0.25) – (70 x 4) + (R B sin70 0 x 5) + (R B cos70 0 x 0) = 0 0 + 0 + 40 – 150 – 43.30 – 6.25 – 280 + (R B x 4.698) + 0 = 0 (R B x 4.698) = – 40 + 150 + 43.30 + 6.25 + 280 R B = 439.55 / 4.698 R B = 93.561 kN Σ F x = 0 H A + 100cos30 - R B cos70 + 25 = 0 H A = -100cos30 + R B cos70 - 25 = - 86.60 + 31.99 - 25 H A = - 79.60 kN (towards left) Or ...